Matematika Diskrit Soal ke-4


Soal :
Berapa banyak permutasi dari huruf ABCDEF jika huruf ABC harus selalu muncul bersama?

Jawab:
ABCDEF
Huruf ABC harus selalu muncul bersama sehingga ABC dihitung 1
Total unsur = 4 karena ABC D E F
Banyak permutasi = nr= 4= 4 * 3 * 2 * 1 = 24 cara.

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